What is the limit as x approaches 1 of (x+2)/(x^3+8) ?

The limit as x approaches 1 of (x+2)/(x^3+8) is 1/3

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limit as x approaches 1 of (x+2)/(x^3+8)

x \to 1 lim (\frac{x + 2}{x ^{3} + 8})

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

x \to 1 lim (\frac{x + 2}{x ^{3} + 8})

Plug in the value

x = 1

= \frac{1 + 2}{1 ^{3} + 8}

Simplify

\frac{1 + 2}{1 ^{3} + 8} : \frac{1}{3}

= \frac{1}{3}

\int \frac{2}{x ln ^{3} ( x )} d x

\frac{\partial}{\partial x} (x^{4} ln (yz))

n = 1 \sum \infty \frac{1}{1 0 ^{n}}

n = 1 \sum \infty (\frac{2}{7}) \cdot n

\int sin^{4} (\frac{x}{2}) cos^{2} (\frac{x}{2}) d x

What is the limit as x approaches 1 of (x+2)/(x^3+8) ?
The limit as x approaches 1 of (x+2)/(x^3+8) is 1/3