What is the sum from n=1 to infinity of (2/7)*n ?

The sum from n=1 to infinity of (2/7)*n is diverges

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sum from n=1 to infinity of (2/7)*n

n = 1 \sum \infty (\frac{2}{7}) \cdot n

diverges

Solution steps

n = 1 \sum \infty \frac{2}{7} n

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{2}{7} \cdot n = 1 \sum \infty n

Apply Series Divergence Test:

diverges

= \frac{2}{7} diverges

= diverges

\int sin^{4} (\frac{x}{2}) cos^{2} (\frac{x}{2}) d x

\int 2 t + 2 d t

n = 0 \sum \infty \frac{- 14}{8}

\frac{d}{d x} (3 sin (x) + 2 cos (x) tan (x))

What is the sum from n=1 to infinity of (2/7)*n ?
The sum from n=1 to infinity of (2/7)*n is diverges