What is the derivative of 3sin(x+2cos(x)tan(x)) ?

The derivative of 3sin(x+2cos(x)tan(x)) is 5cos(x)

What is the first derivative of 3sin(x+2cos(x)tan(x)) ?

The first derivative of 3sin(x+2cos(x)tan(x)) is 5cos(x)

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\frac{d}{d x} (3 sin (x) + 2 cos (x) tan (x))

5 cos (x)

Solution steps

\frac{d}{d x} (3 sin (x) + 2 cos (x) tan (x))

Simplify

3 sin (x) + 2 cos (x) tan (x) : 5 sin (x)

= \frac{d}{d x} (5 sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sin (x))

Apply the common derivative:

\frac{d}{d x} (sin (x)) = cos (x)

= 5 cos (x)

2 x + 1, x^{3} - 5 x^{2} + 6 x + 1

\int - 30 x^{\frac{2}{3}} d x

\frac{d y}{d x} = \frac{( e ^{x - y} )}{1 + e ^{x}}

\int_{0}^{2} 30000 e^{0.03 x} d x

\int 36 t^{8} e^{- t^{9}} d t

What is the derivative of 3sin(x+2cos(x)tan(x)) ?
The derivative of 3sin(x+2cos(x)tan(x)) is 5cos(x)
What is the first derivative of 3sin(x+2cos(x)tan(x)) ?
The first derivative of 3sin(x+2cos(x)tan(x)) is 5cos(x)