What is the integral of (sin^2(x))/((1+sin(x))) ?

The integral of (sin^2(x))/((1+sin(x))) is -2/(tan(x/2)+1)-cos(x)-x+C

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integral of (sin^2(x))/((1+sin(x)))

integral

\frac{sin ^{2} ( x )}{( 1 + sin ( x ) )}

- \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x + C

Solution steps

\int \frac{sin ^{2} ( x )}{1 + sin ( x )} d x

Rewrite using trig identities

= \int \frac{1 - cos ^{2} ( x )}{1 + sin ( x )} d x

Expand

\frac{1 - cos ^{2} ( x )}{1 + sin ( x )} : \frac{1}{1 + sin ( x )} - \frac{cos ^{2} ( x )}{1 + sin ( x )}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{1 + sin ( x )} d x - \int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x

\int \frac{1}{1 + sin ( x )} d x = - \frac{2}{tan ( \frac{x}{2} ) + 1}

\int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x = cos (x) + x

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - (cos (x) + x)

Simplify

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x

Add a constant to the solution

= - \frac{2}{tan ( \frac{x}{2} ) + 1} - cos (x) - x + C

\frac{3}{x ( x + 3 )}

\frac{2}{x ^{\frac{1}{3}}}

\frac{1}{( t t ^{2} - 1 )}

(x + 1)^{- 3}

\frac{1}{a + x ^{2}}

What is the integral of (sin^2(x))/((1+sin(x))) ?
The integral of (sin^2(x))/((1+sin(x))) is -2/(tan(x/2)+1)-cos(x)-x+C