What is the f(x)=(3x+3)/((3-8x+x^2)^{1/2)} ?

The f(x)=(3x+3)/((3-8x+x^2)^{1/2)} is

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f(x)=(3x+3)/((3-8x+x^2)^{1/2)}

f (x) = \frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}}

Domain : x < 4 - 1 3^{\frac{1}{2}} or x > 4 + 1 3^{\frac{1}{2}}

Range : f (x) > - 3

X Intercepts : (- 1, 0), Y Intercepts : (0, 3^{\frac{1}{2}})

Asymptotes : Vertical x = 4 - 1 3^{\frac{1}{2}}, x = 4 + 1 3^{\frac{1}{2}}, Horizontal y = 3, y = - 3

Extreme Points : None

Interval Notation

Domain : (- \infty, 4 - 1 3^{\frac{1}{2}}) \cup (4 + 1 3^{\frac{1}{2}}, \infty)

Range : (- 3, \infty)

Solution steps

Domain of

\frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}} : x < 4 - 1 3^{\frac{1}{2}} or x > 4 + 1 3^{\frac{1}{2}}

Range of

\frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}} : f (x) > - 3

Axis interception points of

\frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}} :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, 3^{\frac{1}{2}})

Asymptotes of

\frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}} :

Vertical

: x = 4 - 1 3^{\frac{1}{2}}, x = 4 + 1 3^{\frac{1}{2}},

Horizontal

: y = 3, y = - 3

Extreme Points of

\frac{3 x + 3}{( 3 - 8 x + x ^{2} ) ^{\frac{1}{2}}} :

None

x^{5} (x^{3} + 4)^{\frac{1}{2}}

x^{2} x \cdot 1

\frac{x}{( x ^{2} + x + 1 )}

sin^{3} (x) cos^{2} (x)

\frac{x}{( x ^{2} + 4 ) ^{2}}

What is the f(x)=(3x+3)/((3-8x+x^2)^{1/2)} ?
The f(x)=(3x+3)/((3-8x+x^2)^{1/2)} is