What is the solution for (d^2-4)y=e^2x ?

The solution for (d^2-4)y=e^2x is y=c_{1}e^{2x}+c_{2}e^{-2x}-(e^2x)/4

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(d^2-4)y=e^2x

(d^{2} - 4) y = e^{2} x

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{e ^{2} x}{4}

Solution steps

(d^{2} - 4) y = e^{2} x

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{e ^{2} x}{4}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - \frac{e ^{2} x}{4}

(d^{3} + 2 d^{2} + d) y = e^{2} x + x^{2} + x

(d^{2} + 1) y = x^{2} e^{2} x

y^{^{''}} + y = \frac{1}{sin ( x )}

y^{^{''}} - 4 y^{^{'}} - 5 y = 4 x^{2} e^{2 x}

(d^{2} - 6 d + 9) \cdot y = x^{2} \cdot e^{2 x}

What is the solution for (d^2-4)y=e^2x ?
The solution for (d^2-4)y=e^2x is y=c_{1}e^{2x}+c_{2}e^{-2x}-(e^2x)/4