What is the solution for (d^2-d-2)y=6e^{(-t)/2} ?

The solution for (d^2-d-2)y=6e^{(-t)/2} is y=c_{1}e^{2t}+c_{2}e^{-t}-24/5 e^{-t/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2-d-2)y=6e^{(-t)/2}

(d^{2} - d - 2) y = 6 e^{\frac{- t}{2}}

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

Solution steps

(d^{2} - d - 2) y = 6 e^{\frac{- t}{2}}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

y = c_{1} e^{2 t} + c_{2} e^{- t} - \frac{24}{5} e^{- \frac{t}{2}}

d, d (q) = - 0.4 q + 23

(d^{2} + 4) y = 4 sin^{2} (x)

(d^{4} + 2 d^{3} - 3 d^{2}) y = 3 e^{2} x + 4 sin (x)

(d^{2} - 4) y = 3 e^{2} x - 4 e^{- 2} x

y^{^{''}} + 4 y = e^{2} t

What is the solution for (d^2-d-2)y=6e^{(-t)/2} ?
The solution for (d^2-d-2)y=6e^{(-t)/2} is y=c_{1}e^{2t}+c_{2}e^{-t}-24/5 e^{-t/2}