en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2-2d-3)y=5

Solution

(d^{2} - 2 d - 3) y = 5

Solution

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

Solution steps

(d^{2} - 2 d - 3) y = 5

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{5}{3}

Graph

Popular Examples

(d^{3} - d) \cdot y = x

(d^2+2d+3)y=sin(x)

(d^{2} + 2 d + 3) y = sin (x)

y^{'''}-3y^{''}+4y^'-2y=e^x

y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} - 2 y = e^{x}

y^{''}-6y^'+9y=2,y^'(0)=17

y^{^{''}} - 6 y^{^{'}} + 9 y = 2, y^{^{'}} (0) = 17

(d^2-1)y=xsin^3(x)+cos(x)

(d^{2} - 1) y = x sin^{3} (x) + cos (x)

Frequently Asked Questions (FAQ)

What is the solution for (d^2-2d-3)y=5 ?
The solution for (d^2-2d-3)y=5 is y=c_{1}e^{3x}+c_{2}e^{-x}-5/3