What is the solution for (d^2-d-2)y=10cos(x) ?

The solution for (d^2-d-2)y=10cos(x) is y=c_{1}e^{2x}+c_{2}e^{-x}-sin(x)-3cos(x)

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(d^2-d-2)y=10cos(x)

(d^{2} - d - 2) y = 10 cos (x)

y = c_{1} e^{2 x} + c_{2} e^{- x} - sin (x) - 3 cos (x)

Solution steps

(d^{2} - d - 2) y = 10 cos (x)

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} - sin (x) - 3 cos (x)

y = c_{1} e^{2 x} + c_{2} e^{- x} - sin (x) - 3 cos (x)

y^{^{''}} + 4 y^{^{'}} + 3 y = 4, e^{3} t y (0) = 2, y^{^{'}} (0) = 7

y^{^{''}} - 5 y^{^{'}} - 6 y = 6 x^{2} - 4 x - 3

(d^{2} + 4) y = sin^{2} (x)

(d^{2} - 2 d + 2) y = e^{x} tan (x)

y^{^{''}} - y^{^{'}} - 6 y = 11

What is the solution for (d^2-d-2)y=10cos(x) ?
The solution for (d^2-d-2)y=10cos(x) is y=c_{1}e^{2x}+c_{2}e^{-x}-sin(x)-3cos(x)