What is the tangent of y=x^8e^{-x},(1, 1/e) ?

The tangent of y=x^8e^{-x},(1, 1/e) is y= 7/e x-6/e

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tangent of y=x^8e^{-x},(1, 1/e)

tangent of

y = x^{8} e^{- x}, (1, \frac{1}{e})

y = \frac{7}{e} x - \frac{6}{e}

Solution steps

Find the slope of

y = x^{8} e^{- x} : \frac{d y}{d x} = 8 e^{- x} x^{7} - e^{- x} x^{8}

Compute the slope of

y = x^{8} e^{- x}

(1, \frac{1}{e}) : m = \frac{7}{e}

Find the line with slope m=

\frac{7}{e}

and passing through

(1, \frac{1}{e}) : y = \frac{7}{e} x - \frac{6}{e}

y = \frac{7}{e} x - \frac{6}{e}

\int (2 x^{4} - 8 x^{3}) \cdot e^{- 3 x} d x

\frac{d}{d x} (\frac{2 cos ( x )}{sec ( x )})

y^{^{''}} + y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

(2 x y) d y + (x^{2} + y^{2}) d x = 0

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = 1

What is the tangent of y=x^8e^{-x},(1, 1/e) ?
The tangent of y=x^8e^{-x},(1, 1/e) is y= 7/e x-6/e