What is the solution for y^{''}+y^'+6y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+y^'+6y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+y^'+6y=0,y(0)=0,y^'(0)=0

y^{^{''}} + y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + y^{'} (t) + 6 y = 0

Solve linear ODE:

y = 0

y = 0

(2 x y) d y + (x^{2} + y^{2}) d x = 0

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = 1

y = (tan (x))^{\frac{9}{x}}

\int (x^{2} x) d x

6 x^{\frac{1}{4}}

What is the solution for y^{''}+y^'+6y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+y^'+6y=0,y(0)=0,y^'(0)=0 is y=0