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Popular >

f^'(x)=x^{1/x}

Solution

f^{^{'}} (x) = x^{\frac{1}{x}}

Solution

f (x) = \int x^{\frac{1}{x}} d x

Solution steps

f^{'} (x) = x^{\frac{1}{x}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x^{\frac{1}{x}} d x

f (x) = \int x^{\frac{1}{x}} d x

Popular Examples

18x+y^'=20,-3xy(1)=2

18 x + y^{^{'}} = 20, - 3 x y (1) = 2

2y^'=((1-sin(x))^{-1})/2

2 y^{^{'}} = \frac{( 1 - sin ( x ) ) ^{- 1}}{2}

f^'(x)=2(x^2+x)^5

f^{^{'}} (x) = 2 (x^{2} + x)^{5}

(x^2y^{''}+1)/(4(x+3/4)y)=0

\frac{x ^{2} y ^{^{''}} + 1}{4 ( x + \frac{3}{4} ) y} = 0

f^'(x)=(x^2+x-1)/(x+1)

f^{^{'}} (x) = \frac{x ^{2} + x - 1}{x + 1}

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=x^{1/x} ?
The solution for f^'(x)=x^{1/x} is f(x)=integral of x^{1/x}