What is the solution for x^3(dy)/(dx)+y^2=x^2y ?

The solution for x^3(dy)/(dx)+y^2=x^2y is y=(x^2)/(-1+c_{1)x}

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x^3(dy)/(dx)+y^2=x^2y

x^{3} \frac{d y}{d x} + y^{2} = x^{2} y

y = \frac{x ^{2}}{- 1 + c _{1} x}

Solution steps

x^{3} \frac{d y}{d x} + y^{2} = x^{2} y

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- 1 + c _{1} x}

y = \frac{x ^{2}}{- 1 + c _{1} x}

\frac{3 x ^{2} + 1}{2 x ^{2} - 5}

f (x) = x^{3} x

x \to - 3 + lim (x^{3} + 27)

\int_{0}^{8} e^{x} sin (x) d x

\frac{\partial}{\partial u} (u^{2} + v)

What is the solution for x^3(dy)/(dx)+y^2=x^2y ?
The solution for x^3(dy)/(dx)+y^2=x^2y is y=(x^2)/(-1+c_{1)x}