What is the derivative of 2cos(x+sin(2x)) ?

The derivative of 2cos(x+sin(2x)) is -2sin(x)+cos(2x)*2

What is the first derivative of 2cos(x+sin(2x)) ?

The first derivative of 2cos(x+sin(2x)) is -2sin(x)+cos(2x)*2

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\frac{d}{d x} (2 cos (x) + sin (2 x))

- 2 sin (x) + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 cos (x) + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= - 2 sin (x) + cos (2 x) \cdot 2

\frac{d}{d x} (a x + \frac{b}{x})

\frac{d}{d x} (\frac{e ^{x}}{x ^{2} - 1})

e^{- 7 t}

\int x \cdot sin (x) cos (x) d x

n = 7 \sum \infty \frac{1}{n ln ( n )}

What is the derivative of 2cos(x+sin(2x)) ?
The derivative of 2cos(x+sin(2x)) is -2sin(x)+cos(2x)*2
What is the first derivative of 2cos(x+sin(2x)) ?
The first derivative of 2cos(x+sin(2x)) is -2sin(x)+cos(2x)*2