What is the integral of 6^xx ?

The integral of 6^xx is (6^xx)/(ln(6))-(6^x)/(ln^2(6))+C

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integral of 6^xx

\int 6^{x} x d x

\frac{6 ^{x} x}{ln ( 6 )} - \frac{6 ^{x}}{ln ^{2} ( 6 )} + C

Solution steps

\int 6^{x} x d x

Apply Integration By Parts

: \frac{6 ^{x} x}{ln ( 6 )} - \int \frac{6 ^{x}}{ln ( 6 )} d x

= \frac{6 ^{x} x}{ln ( 6 )} - \int \frac{6 ^{x}}{ln ( 6 )} d x

\int \frac{6 ^{x}}{ln ( 6 )} d x = \frac{6 ^{x}}{ln ^{2} ( 6 )}

= \frac{6 ^{x} x}{ln ( 6 )} - \frac{6 ^{x}}{ln ^{2} ( 6 )}

Add a constant to the solution

= \frac{6 ^{x} x}{ln ( 6 )} - \frac{6 ^{x}}{ln ^{2} ( 6 )} + C

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What is the integral of 6^xx ?
The integral of 6^xx is (6^xx)/(ln(6))-(6^x)/(ln^2(6))+C