What is the integral of 50-3xe^{0.01x^2} ?

The integral of 50-3xe^{0.01x^2} is 50x-150e^{0.01x^2}+C

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integral of 50-3xe^{0.01x^2}

\int 50 - 3 x e^{0.01 x^{2}} d x

50 x - 150 e^{0.01 x^{2}} + C

Solution steps

\int 50 - 3 x e^{0.01 x^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 50 d x - \int 3 x e^{0.01 x^{2}} d x

\int 50 d x = 50 x

\int 3 x e^{0.01 x^{2}} d x = 150 e^{0.01 x^{2}}

= 50 x - 150 e^{0.01 x^{2}}

Add a constant to the solution

= 50 x - 150 e^{0.01 x^{2}} + C

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What is the integral of 50-3xe^{0.01x^2} ?
The integral of 50-3xe^{0.01x^2} is 50x-150e^{0.01x^2}+C