What is the integral of (e^{3p-7}) ?

The integral of (e^{3p-7}) is 1/3 e^{3p-7}+C

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integral of (e^{3p-7})

\int (e^{3 p - 7}) d p

\frac{1}{3} e^{3 p - 7} + C

Solution steps

\int e^{3 p - 7} d p

Apply u-substitution

: \int e^{u} \frac{1}{3} d u

= \int e^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{3} e^{u}

Substitute back

u = 3 p - 7

= \frac{1}{3} e^{3 p - 7}

Add a constant to the solution

= \frac{1}{3} e^{3 p - 7} + C

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What is the integral of (e^{3p-7}) ?
The integral of (e^{3p-7}) is 1/3 e^{3p-7}+C