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Popular >

x^2y^'+(2-y)=0

Solution

x^{2} y^{^{'}} + (2 - y) = 0

Solution

y = e^{- \frac{1}{x} + c_{1}} + 2

Solution steps

x^{2} y^{'} (x) + (2 - y) = 0

Solve separable ODE:

y = e^{- \frac{1}{x} + c_{1}} + 2

y = e^{- \frac{1}{x} + c_{1}} + 2

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(\partial)/(\partial x)(3^x)

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t^2y^'+2ty-y^3=0

t^{2} y^{^{'}} + 2 t y - y^{3} = 0

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+(2-y)=0 ?
The solution for x^2y^'+(2-y)=0 is y=e^{-1/x+c_{1}}+2