What is the tangent of tan^2(x) ?

The tangent of tan^2(x) is y=2tan(a_{0})sec^2(a_{0})x+tan^2(a_{0})-2tan(a_{0})sec^2(a_{0})a_{0}

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tangent of tan^2(x)

tangent of

tan^{2} (x)

y = 2 tan (a_{0}) sec^{2} (a_{0}) x + tan^{2} (a_{0}) - 2 tan (a_{0}) sec^{2} (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, tan^{2} (a_{0}))

Find the slope of

y = tan^{2} (x) : \frac{d y}{d x} = 2 tan (x) sec^{2} (x)

Compute the slope of

y = tan^{2} (x)

x = a_{0} : m = 2 tan (a_{0}) sec^{2} (a_{0})

Find the line with slope m=

2 tan (a_{0}) sec^{2} (a_{0})

and passing through

(a_{0}, tan^{2} (a_{0})) : y = 2 tan (a_{0}) sec^{2} (a_{0}) x + tan^{2} (a_{0}) - 2 tan (a_{0}) sec^{2} (a_{0}) a_{0}

y = 2 tan (a_{0}) sec^{2} (a_{0}) x + tan^{2} (a_{0}) - 2 tan (a_{0}) sec^{2} (a_{0}) a_{0}

y^{^{'}} = y - x^{2} + 1, y (0) = 0

\int \frac{b - x}{x} d x

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{3}})

x \to 0 lim (\frac{x - 20}{x - 4})

\frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} + y = 2

What is the tangent of tan^2(x) ?
The tangent of tan^2(x) is y=2tan(a_{0})sec^2(a_{0})x+tan^2(a_{0})-2tan(a_{0})sec^2(a_{0})a_{0}