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Popular >

y^'=y-x^2+1,y(0)=0

Solution

y^{^{'}} = y - x^{2} + 1, y (0) = 0

Solution

y = x^{2} + 2 x + 1 - e^{x}

Solution steps

y^{'} (x) = y - x^{2} + 1

Solve linear ODE:

y = x^{2} + 2 x + 1 - e^{x}

y = x^{2} + 2 x + 1 - e^{x}

Popular Examples

integral of (b-x)/x

\int \frac{b - x}{x} d x

(\partial)/(\partial x)((e^y)/(x+y^3))

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{3}})

limit as x approaches 0 of (x-20)/(x-4)

x \to 0 lim (\frac{x - 20}{x - 4})

(d^2y)/(dt^2)+2(dy)/(dt)+y=2

\frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} + y = 2

integral of m 1 (v)(v)

\int m \frac{d}{1} (v) (v) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-x^2+1,y(0)=0 ?
The solution for y^'=y-x^2+1,y(0)=0 is y=x^2+2x+1-e^x