What is the integral of m 1 (v)(v) ?

The integral of m 1 (v)(v) is mdv^2x+C

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integral of m 1 (v)(v)

\int m \frac{d}{1} (v) (v) d x

m d v^{2} x + C

Solution steps

\int m \frac{d}{1} vv d x

Integral of a constant:

\int a d x = a x

= \frac{d}{1} m vvx

Simplify

\frac{d}{1} m vvx : m d v^{2} x

= m d v^{2} x

Add a constant to the solution

= m d v^{2} x + C

\int \frac{1}{a - x} d x

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\frac{\partial}{\partial z} (2 x^{2} + 2 yz)

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\frac{12}{( 3 s - 5 )}