What is the integral of (32)/(y^3) ?

The integral of (32)/(y^3) is -(16)/(y^2)+C

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integral of (32)/(y^3)

\int \frac{32}{y ^{3}} d y

- \frac{16}{y ^{2}} + C

Solution steps

\int \frac{32}{y ^{3}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 32 \cdot \int \frac{1}{y ^{3}} d y

Apply the Power Rule

: - \frac{1}{2 y ^{2}}

= 32 (- \frac{1}{2 y ^{2}})

Simplify

32 (- \frac{1}{2 y ^{2}}) : - \frac{16}{y ^{2}}

= - \frac{16}{y ^{2}}

Add a constant to the solution

= - \frac{16}{y ^{2}} + C

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What is the integral of (32)/(y^3) ?
The integral of (32)/(y^3) is -(16)/(y^2)+C