What is the derivative of x^2+6x-16 ?

The derivative of x^2+6x-16 is 2x+6

What is the first derivative of x^2+6x-16 ?

The first derivative of x^2+6x-16 is 2x+6

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\frac{d}{d x} (x^{2} + 6 x - 16)

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x - 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (16)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (16) = 0

= 2 x + 6 - 0

Simplify

= 2 x + 6

\frac{\partial}{\partial h} (π r^{2} h)

\frac{\partial}{\partial x} (sin (x) sin (y))

(x \cdot \frac{d y}{d x} - y) cos (\frac{y}{x}) + x = 0

\int \frac{x ^{6} + 2 x ^{4} + 6 x - 9}{x ^{3} + 3} d x

\frac{6}{( 1 - x ) ^{3}}

What is the derivative of x^2+6x-16 ?
The derivative of x^2+6x-16 is 2x+6
What is the first derivative of x^2+6x-16 ?
The first derivative of x^2+6x-16 is 2x+6