What is the integral of (x/3)^2 ?

The integral of (x/3)^2 is (x^3)/9-(2x^3)/(27)+C

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integral of (x/3)^2

\int (\frac{x}{3})^{2} d x

\frac{x ^{3}}{9} - \frac{2 x ^{3}}{27} + C

Solution steps

\int (\frac{x}{3})^{2} d x

Apply Integration By Parts

: \frac{x ^{3}}{9} - \int \frac{2 x ^{2}}{9} d x

= \frac{x ^{3}}{9} - \int \frac{2 x ^{2}}{9} d x

\int \frac{2 x ^{2}}{9} d x = \frac{2 x ^{3}}{27}

= \frac{x ^{3}}{9} - \frac{2 x ^{3}}{27}

Add a constant to the solution

= \frac{x ^{3}}{9} - \frac{2 x ^{3}}{27} + C

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What is the integral of (x/3)^2 ?
The integral of (x/3)^2 is (x^3)/9-(2x^3)/(27)+C