What is the tangent of y=7+8x+2xe^x,(0,7) ?

The tangent of y=7+8x+2xe^x,(0,7) is y=10x+7

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tangent of y=7+8x+2xe^x,(0,7)

tangent of

y = 7 + 8 x + 2 x e^{x}, (0, 7)

y = 10 x + 7

Solution steps

Find the slope of

y = 7 + 8 x + 2 x e^{x} : \frac{d y}{d x} = 2 (e^{x} x + e^{x}) + 8

Compute the slope of

y = 7 + 8 x + 2 x e^{x}

(0, 7) : m = 10

Find the line with slope m=

10

and passing through

(0, 7) : y = 10 x + 7

y = 10 x + 7

(3.5) (- 1.5)

t^{n}

(x + 2 y) d y - y d x = 0

x \to 2 lim (x^{3} + 2 x - 5)

\frac{d ^{2}}{d x ^{2}} (e^{x} - x^{6})

What is the tangent of y=7+8x+2xe^x,(0,7) ?
The tangent of y=7+8x+2xe^x,(0,7) is y=10x+7