What is the solution for (x+2y)dy-ydx=0 ?

The solution for (x+2y)dy-ydx=0 is y= x/(2\W(\frac{x){c_{1}})}

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(x+2y)dy-ydx=0

(x + 2 y) d y - y d x = 0

y = \frac{x}{2 W ( \frac{x}{c _{1}} )}

Solution steps

(x + 2 y) d y - y d x = 0

Solve using substitution:

y = \frac{x}{2 W ( \frac{x}{c _{1}} )}

y = \frac{x}{2 W ( \frac{x}{c _{1}} )}

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What is the solution for (x+2y)dy-ydx=0 ?
The solution for (x+2y)dy-ydx=0 is y= x/(2\W(\frac{x){c_{1}})}