What is the derivative of f(x)=9e^xcos(x) ?

The derivative of f(x)=9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))

What is the first derivative of f(x)=9e^xcos(x) ?

The first derivative of f(x)=9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))

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derivative of

f (x) = 9 e^{x} cos (x)

9 (e^{x} cos (x) - e^{x} sin (x))

Solution steps

\frac{d}{d x} (9 e^{x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x)

= 9 (\frac{d}{d x} (e^{x}) cos (x) + \frac{d}{d x} (cos (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x)) = - sin (x)

= 9 (e^{x} cos (x) + (- sin (x)) e^{x})

Simplify

= 9 (e^{x} cos (x) - e^{x} sin (x))

\int sin (x) (cos (2 x)) d x

n = 1 \sum \infty \frac{1}{1 + 4 ^{n}}

n = 0 \sum \infty a^{n}

\frac{d}{d x} ((5 x^{3} - 2 x^{2}) (6 x^{3}))

\frac{d}{d x} (1 - \frac{x ^{2}}{16})

What is the derivative of f(x)=9e^xcos(x) ?
The derivative of f(x)=9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))
What is the first derivative of f(x)=9e^xcos(x) ?
The first derivative of f(x)=9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))