What is the sum from n=1 to infinity of 1/(1+4^n) ?

The sum from n=1 to infinity of 1/(1+4^n) is converges

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sum from n=1 to infinity of 1/(1+4^n)

n = 1 \sum \infty \frac{1}{1 + 4 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{1 + 4 ^{n}}

Apply Series Ratio Test:

converges

= converges

n = 0 \sum \infty a^{n}

\frac{d}{d x} ((5 x^{3} - 2 x^{2}) (6 x^{3}))

\frac{d}{d x} (1 - \frac{x ^{2}}{16})

y^{2} d x + x (x - y) d y = 0

\int_{- 1}^{1} 2 x d x

What is the sum from n=1 to infinity of 1/(1+4^n) ?
The sum from n=1 to infinity of 1/(1+4^n) is converges