What is the integral of (x^2-4x+5)/(2x) ?

The integral of (x^2-4x+5)/(2x) is 1/2 ((x^2)/2-4x+5ln|x|)+C

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integral of (x^2-4x+5)/(2x)

\int \frac{x ^{2} - 4 x + 5}{2 x} d x

\frac{1}{2} (\frac{x ^{2}}{2} - 4 x + 5 ln ∣ x ∣) + C

Solution steps

\int \frac{x ^{2} - 4 x + 5}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{x ^{2} - 4 x + 5}{x} d x

Expand

\frac{x ^{2} - 4 x + 5}{x} : x - 4 + \frac{5}{x}

= \frac{1}{2} \cdot \int x - 4 + \frac{5}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int x d x - \int 4 d x + \int \frac{5}{x} d x)

\int x d x = \frac{x ^{2}}{2}

\int 4 d x = 4 x

\int \frac{5}{x} d x = 5 ln ∣ x ∣

= \frac{1}{2} (\frac{x ^{2}}{2} - 4 x + 5 ln ∣ x ∣)

Add a constant to the solution

= \frac{1}{2} (\frac{x ^{2}}{2} - 4 x + 5 ln ∣ x ∣) + C

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What is the integral of (x^2-4x+5)/(2x) ?
The integral of (x^2-4x+5)/(2x) is 1/2 ((x^2)/2-4x+5ln|x|)+C