What is the integral of-8sin(7x) ?

The integral of-8sin(7x) is 8/7 cos(7x)+C

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integral of-8sin(7x)

\int - 8 sin (7 x) d x

\frac{8}{7} cos (7 x) + C

Solution steps

\int - 8 sin (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 8 \cdot \int sin (7 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{7} d u

= - 8 \cdot \int sin (u) \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 8 \cdot \frac{1}{7} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - 8 \cdot \frac{1}{7} (- cos (u))

Substitute back

u = 7 x

= - 8 \cdot \frac{1}{7} (- cos (7 x))

Simplify

- 8 \cdot \frac{1}{7} (- cos (7 x)) : \frac{8}{7} cos (7 x)

= \frac{8}{7} cos (7 x)

Add a constant to the solution

= \frac{8}{7} cos (7 x) + C

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