What is the derivative of f(x)=(x^2-36)/(x-6) ?

The derivative of f(x)=(x^2-36)/(x-6) is 1

What is the first derivative of f(x)=(x^2-36)/(x-6) ?

The first derivative of f(x)=(x^2-36)/(x-6) is 1

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derivative of

f (x) = \frac{x ^{2} - 36}{x - 6}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 36}{x - 6})

Simplify

\frac{x ^{2} - 36}{x - 6} : x + 6

= \frac{d}{d x} (x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (6)

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 1 + 0

Simplify

= 1

\frac{\partial}{\partial x} (4 x^{2} + y^{2})

y^{^{''}} - 7 y^{^{'}} = 49 t

y^{^{''}} = 9 y

\frac{\partial}{\partial y} (2 y x)

\frac{d}{d x} (\frac{- 1}{2 ( x + 1 )})

What is the derivative of f(x)=(x^2-36)/(x-6) ?
The derivative of f(x)=(x^2-36)/(x-6) is 1
What is the first derivative of f(x)=(x^2-36)/(x-6) ?
The first derivative of f(x)=(x^2-36)/(x-6) is 1