What is the integral of \sqrt[3]{6x} ?

The integral of \sqrt[3]{6x} is \sqrt[3]{6}x\sqrt[3]{x}-3/(2\sqrt[3]{9)*2^{2/3}}x^{4/3}+C

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integral of \sqrt[3]{6x}

Solution steps

Apply Integration By Parts

Add a constant to the solution

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What is the integral of \sqrt[3]{6x} ?
The integral of \sqrt[3]{6x} is \sqrt[3]{6}x\sqrt[3]{x}-3/(2\sqrt[3]{9)*2^{2/3}}x^{4/3}+C