What is the integral of e^{1/50 t} ?

The integral of e^{1/50 t} is 50e^{1/50 t}+C

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integral of e^{1/50 t}

\int e^{\frac{1}{50} t} d t

50 e^{\frac{1}{50} t} + C

Solution steps

\int e^{\frac{1}{50} t} d t

Apply u-substitution

: \int e^{u} \cdot 50 d u

= \int e^{u} \cdot 50 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 50 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 50 e^{u}

Substitute back

u = \frac{1}{50} t

= 50 e^{\frac{1}{50} t}

Add a constant to the solution

= 50 e^{\frac{1}{50} t} + C

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What is the integral of e^{1/50 t} ?
The integral of e^{1/50 t} is 50e^{1/50 t}+C