What is the integral of (2/y+y^2)e^x ?

The integral of (2/y+y^2)e^x is (2/y+y^2)e^x+C

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integral of (2/y+y^2)e^x

\int (\frac{2}{y} + y^{2}) e^{x} d x

(\frac{2}{y} + y^{2}) e^{x} + C

Solution steps

\int (\frac{2}{y} + y^{2}) e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (\frac{2}{y} + y^{2}) \cdot \int e^{x} d x

\int e^{x} d x = e^{x}

= (\frac{2}{y} + y^{2}) e^{x}

Add a constant to the solution

= (\frac{2}{y} + y^{2}) e^{x} + C

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What is the integral of (2/y+y^2)e^x ?
The integral of (2/y+y^2)e^x is (2/y+y^2)e^x+C