What is (\partial)/(\partial x)(-2xyz^2+12) ?

The answer to (\partial)/(\partial x)(-2xyz^2+12) is -2yz^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(-2xyz^2+12)

\frac{\partial}{\partial x} (- 2 x y z^{2} + 12)

- 2 y z^{2}

Solution steps

\frac{\partial}{\partial x} (- 2 x y z^{2} + 12)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (2 x y z^{2}) + \frac{\partial}{\partial x} (12)

\frac{\partial}{\partial x} (2 x y z^{2}) = 2 y z^{2}

\frac{\partial}{\partial x} (12) = 0

= - 2 y z^{2} + 0

Simplify

= - 2 y z^{2}

10 sin (6 t)

\int \frac{x}{x - x ^{2}} d x

k = 2 \sum \infty (\frac{1}{3})^{k}

y = arcsin (x) + 1 - x^{2}

\frac{\partial}{\partial v} (uv - 1)

What is (\partial)/(\partial x)(-2xyz^2+12) ?
The answer to (\partial)/(\partial x)(-2xyz^2+12) is -2yz^2