What is (\partial)/(\partial v)(uv-1) ?

The answer to (\partial)/(\partial v)(uv-1) is u

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(\partial)/(\partial v)(uv-1)

\frac{\partial}{\partial v} (uv - 1)

u

Solution steps

\frac{\partial}{\partial v} (uv - 1)

Treat

u

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (uv) - \frac{\partial}{\partial v} (1)

\frac{\partial}{\partial v} (uv) = u

\frac{\partial}{\partial v} (1) = 0

= u - 0

Simplify

= u

\frac{d}{d x} (4 x + \frac{64}{x})

f (x) = 3 x - 9

\int \frac{x ^{3} + 3}{x ^{2} + 3 x + 2} d x

f (x) = \frac{4 x}{x ^{2} + 1}, (- 1, - 2)

x \to 3 lim (\frac{x ^{2} - 2 x + 1}{2})

What is (\partial)/(\partial v)(uv-1) ?
The answer to (\partial)/(\partial v)(uv-1) is u