What is the derivative of 2x^3-x^2+4 ?

The derivative of 2x^3-x^2+4 is 6x^2-2x

What is the first derivative of 2x^3-x^2+4 ?

The first derivative of 2x^3-x^2+4 is 6x^2-2x

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derivative of

2 x^{3} - x^{2} + 4

6 x^{2} - 2 x

Solution steps

\frac{d}{d x} (2 x^{3} - x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 6 x^{2} - 2 x + 0

Simplify

= 6 x^{2} - 2 x

10 sin (6 t)

\int \frac{x}{x - x ^{2}} d x

k = 2 \sum \infty (\frac{1}{3})^{k}

y = arcsin (x) + 1 - x^{2}

\frac{\partial}{\partial v} (uv - 1)

What is the derivative of 2x^3-x^2+4 ?
The derivative of 2x^3-x^2+4 is 6x^2-2x
What is the first derivative of 2x^3-x^2+4 ?
The first derivative of 2x^3-x^2+4 is 6x^2-2x