What is the integral of (sec^2(x))/(2+tan(x)) ?

The integral of (sec^2(x))/(2+tan(x)) is ln|2+tan(x)|+C

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integral of (sec^2(x))/(2+tan(x))

\int \frac{sec ^{2} ( x )}{2 + tan ( x )} d x

ln ∣ 2 + tan (x) ∣ + C

Solution steps

\int \frac{sec ^{2} ( x )}{2 + tan ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 2 + tan (x)

= ln ∣ 2 + tan (x) ∣

Add a constant to the solution

= ln ∣ 2 + tan (x) ∣ + C

\int \frac{5 x}{e ^{x}} d x

\int ln (3 x^{3}) d x

\int (- x)^{2} d x

\int \frac{1}{a u ^{2} + b u + c} d u

What is the integral of (sec^2(x))/(2+tan(x)) ?
The integral of (sec^2(x))/(2+tan(x)) is ln|2+tan(x)|+C