What is the integral of x^29^{x^3-1} ?

The integral of x^29^{x^3-1} is 243(x^3-1)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^29^{x^3-1}

\int x^{2} 9^{x^{3} - 1} d x

243 (x^{3} - 1) + C

Solution steps

\int x^{2} \cdot 9^{x^{3} - 1} d x

Apply u-substitution

: \int 243 d u

= \int 243 d u

Integral of a constant:

\int a d x = a x

= 243 u

Substitute back

u = x^{3} - 1

= 243 (x^{3} - 1)

Add a constant to the solution

= 243 (x^{3} - 1) + C

\int \frac{x + 1}{x ^{\frac{5}{2}}} d x

\int \frac{1}{4 + 4 sin ( x )} d x

\int \frac{ln ( x )}{x ^{13}} d x

\int 4 e^{- 2 x} + 5 e^{3 x} d x

\int (\frac{x}{x ^{2} - 9}) d x

What is the integral of x^29^{x^3-1} ?
The integral of x^29^{x^3-1} is 243(x^3-1)+C