What is the integral of 1/((5+x)sqrt(1+x)) ?

The integral of 1/((5+x)sqrt(1+x)) is arctan(1/2 sqrt(x+1))+C

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integral of 1/((5+x)sqrt(1+x))

\int \frac{1}{( 5 + x ) 1 + x} d x

arctan (\frac{1}{2} x + 1) + C

Solution steps

\int \frac{1}{( 5 + x ) 1 + x} d x

Apply u-substitution

: \int \frac{1}{u u - 4} d u

= \int \frac{1}{u u - 4} d u

Apply u-substitution

: \int \frac{2}{v ^{2} + 4} d v

= \int \frac{2}{v ^{2} + 4} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{v ^{2} + 4} d v

Apply Integral Substitution

= 2 \cdot \int \frac{1}{2 ( w ^{2} + 1 )} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{w ^{2} + 1} d w

Use the common integral:

\int \frac{1}{w ^{2} + 1} d w = arctan (w)

= 2 \cdot \frac{1}{2} arctan (w)

Substitute back

= 2 \cdot \frac{1}{2} arctan (\frac{5 + x - 4}{2})

Simplify

2 \cdot \frac{1}{2} arctan (\frac{5 + x - 4}{2}) : arctan (\frac{1}{2} x + 1)

= arctan (\frac{1}{2} x + 1)

Add a constant to the solution

= arctan (\frac{1}{2} x + 1) + C

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What is the integral of 1/((5+x)sqrt(1+x)) ?
The integral of 1/((5+x)sqrt(1+x)) is arctan(1/2 sqrt(x+1))+C