What is (\partial)/(\partial x)(x^3y^4z^2) ?

The answer to (\partial)/(\partial x)(x^3y^4z^2) is 3x^2y^4z^2

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(\partial)/(\partial x)(x^3y^4z^2)

\frac{\partial}{\partial x} (x^{3} y^{4} z^{2})

3 x^{2} y^{4} z^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} y^{4} z^{2})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} z^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} z^{2} \cdot 3 x^{3 - 1}

Simplify

= 3 x^{2} y^{4} z^{2}

y = - \frac{2 x}{x ^{2} + 1}, (1, - 1)

f (x) = x^{3} - 3 x^{2} + 4 x - 7

\frac{d}{d v} (\frac{u}{u + v})

- x^{3} - 5 x^{2} + 2, at x = - 1

\int cos (x) + 2 d x

What is (\partial)/(\partial x)(x^3y^4z^2) ?
The answer to (\partial)/(\partial x)(x^3y^4z^2) is 3x^2y^4z^2