What is the derivative of f(x)=x^3-3x^2+4x-7 ?

The derivative of f(x)=x^3-3x^2+4x-7 is 3x^2-6x+4

What is the first derivative of f(x)=x^3-3x^2+4x-7 ?

The first derivative of f(x)=x^3-3x^2+4x-7 is 3x^2-6x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{3} - 3 x^{2} + 4 x - 7

3 x^{2} - 6 x + 4

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 4 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 3 x^{2} - 6 x + 4 - 0

Simplify

= 3 x^{2} - 6 x + 4

\frac{d}{d v} (\frac{u}{u + v})

- x^{3} - 5 x^{2} + 2, at x = - 1

\int cos (x) + 2 d x

\frac{d}{d x} (6 arcsin (x^{2}))

f (x) = x - \frac{1}{x ^{2}}

What is the derivative of f(x)=x^3-3x^2+4x-7 ?
The derivative of f(x)=x^3-3x^2+4x-7 is 3x^2-6x+4
What is the first derivative of f(x)=x^3-3x^2+4x-7 ?
The first derivative of f(x)=x^3-3x^2+4x-7 is 3x^2-6x+4