What is the derivative of f(x)=x-1/(x^2) ?

The derivative of f(x)=x-1/(x^2) is 1+2/(x^3)

What is the first derivative of f(x)=x-1/(x^2) ?

The first derivative of f(x)=x-1/(x^2) is 1+2/(x^3)

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derivative of

f (x) = x - \frac{1}{x ^{2}}

1 + \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (x - \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 1 - (- \frac{2}{x ^{3}})

Simplify

= 1 + \frac{2}{x ^{3}}

\int 9 + 9 tan^{2} (x) d x

\frac{d}{d x} (x (7 x + 9)^{\frac{1}{3}})

\int \frac{3 x ^{2}}{4} d x

\frac{\partial}{\partial x} (e^{(x - 1)^{2}})

x^{4} + x - 2

What is the derivative of f(x)=x-1/(x^2) ?
The derivative of f(x)=x-1/(x^2) is 1+2/(x^3)
What is the first derivative of f(x)=x-1/(x^2) ?
The first derivative of f(x)=x-1/(x^2) is 1+2/(x^3)