What is (\partial)/(\partial x)(e^{(x-1)^2}) ?

The answer to (\partial)/(\partial x)(e^{(x-1)^2}) is e^{(x-1)^2}*2(x-1)

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(\partial)/(\partial x)(e^{(x-1)^2})

\frac{\partial}{\partial x} (e^{(x - 1)^{2}})

e^{(x - 1)^{2}} \cdot 2 (x - 1)

Solution steps

\frac{\partial}{\partial x} (e^{(x - 1)^{2}})

Apply the chain rule:

e^{(x - 1)^{2}} \frac{\partial}{\partial x} ((x - 1)^{2})

= e^{(x - 1)^{2}} \frac{\partial}{\partial x} ((x - 1)^{2})

\frac{\partial}{\partial x} ((x - 1)^{2}) = 2 (x - 1)

= e^{(x - 1)^{2}} \cdot 2 (x - 1)

x^{4} + x - 2

25 y^{^{''}} + 2 y = 0

f (x) = - x^{3}, (2, - 8)

x \to 0 lim (tan (x))

\int_{- \infty}^{- 1} e^{- 30 t} d t

What is (\partial)/(\partial x)(e^{(x-1)^2}) ?
The answer to (\partial)/(\partial x)(e^{(x-1)^2}) is e^{(x-1)^2}*2(x-1)