What is the first derivative of 7x+4 ?

The first derivative of 7x+4 is 7

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derivative of 7x+4

\frac{d}{d x} (7 x + 4)

7

Solution steps

\frac{d}{d x} (7 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x) + \frac{d}{d x} (4)

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (4) = 0

= 7 + 0

Simplify

= 7

\frac{d y}{d x} = x^{2} + x^{2} y^{2}, y (0) = 1

\frac{\partial}{\partial x} (\frac{0}{0})

\frac{d}{d x} (2 x sin (x) + x^{2} cos (x))

\frac{\partial}{\partial x} (x y^{7} + x^{4} + y^{8})

(- 5, 2), (3, - 7)