What is the integral from 2 to infinity of e^{-6p} ?

The integral from 2 to infinity of e^{-6p} is 1/(6e^{12)}

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integral from 2 to infinity of e^{-6p}

\int_{2}^{\infty} e^{- 6 p} d p

\frac{1}{6 e ^{12}}

Decimal Notation

1.02404 E - 6

Solution steps

\int_{2}^{\infty} e^{- 6 p} d p

Compute the indefinite integral:

\int e^{- 6 p} d p = - \frac{1}{6} e^{- 6 p} + C

Compute the boundaries:

\int_{2}^{\infty} e^{- 6 p} d p = 0 - (- \frac{1}{6 e ^{12}})

= 0 - (- \frac{1}{6 e ^{12}})

Simplify

= \frac{1}{6 e ^{12}}

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\int π sin (x) d x

x \to 6 + lim (x - 6)

What is the integral from 2 to infinity of e^{-6p} ?
The integral from 2 to infinity of e^{-6p} is 1/(6e^{12)}