What is the derivative of y=\sqrt[3]{2x} ?

The derivative of y=\sqrt[3]{2x} is (2^{1/3})/(3x^{2/3)}

What is the first derivative of y=\sqrt[3]{2x} ?

The first derivative of y=\sqrt[3]{2x} is (2^{1/3})/(3x^{2/3)}

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derivative of

\frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x)

= \frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \cdot 2

Simplify

\frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \cdot 2 : \frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

= \frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

\int \frac{1}{5 x - 6} d x

x \to 0 lim (x cot (2 x))

\int_{0}^{25} \frac{4}{5} x d x

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\frac{\partial}{\partial z} (x y^{2} z)

What is the derivative of y=\sqrt[3]{2x} ?
The derivative of y=\sqrt[3]{2x} is (2^{1/3})/(3x^{2/3)}
What is the first derivative of y=\sqrt[3]{2x} ?
The first derivative of y=\sqrt[3]{2x} is (2^{1/3})/(3x^{2/3)}