What is the integral from 0 to 25 of 4/5 x ?

The integral from 0 to 25 of 4/5 x is 250

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integral from 0 to 25 of 4/5 x

\int_{0}^{25} \frac{4}{5} x d x

250

Solution steps

\int_{0}^{25} \frac{4}{5} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{4}{5} \cdot \int_{0}^{25} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{25}

= \frac{4}{5} [\frac{x ^{2}}{2}]_{0}^{25}

Compute the boundaries:

\frac{625}{2}

= \frac{4}{5} \cdot \frac{625}{2}

Simplify

= 250

y^{^{'}} + y = 5 \cdot x + 1

\frac{\partial}{\partial z} (x y^{2} z)

y^{^{''}} + 8 y^{^{'}} + 4 y = 0

f (x) = \frac{x ^{2}}{x ^{2} + 7}

\int - \frac{ln ( x )}{2} d x

What is the integral from 0 to 25 of 4/5 x ?
The integral from 0 to 25 of 4/5 x is 250