What is the integral of 1/(x(x+6)) ?

The integral of 1/(x(x+6)) is 1/6 ln|x|-1/6 ln|x+6|+C

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integral of 1/(x(x+6))

\int \frac{1}{x ( x + 6 )} d x

\frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣ + C

Solution steps

\int \frac{1}{x ( x + 6 )} d x

Take the partial fraction of

\frac{1}{x ( x + 6 )} : \frac{1}{6 x} - \frac{1}{6 ( x + 6 )}

= \int \frac{1}{6 x} - \frac{1}{6 ( x + 6 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{6 x} d x - \int \frac{1}{6 ( x + 6 )} d x

\int \frac{1}{6 x} d x = \frac{1}{6} ln ∣ x ∣

\int \frac{1}{6 ( x + 6 )} d x = \frac{1}{6} ln ∣ x + 6 ∣

= \frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣

Add a constant to the solution

= \frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣ + C

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What is the integral of 1/(x(x+6)) ?
The integral of 1/(x(x+6)) is 1/6 ln|x|-1/6 ln|x+6|+C