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Popular >

2ty^'-3y=0

Solution

2 t y^{^{'}} - 3 y = 0

Solution

y = c_{1} t^{\frac{3}{2}}

Solution steps

2 t y^{'} (t) - 3 y = 0

Solve separable ODE:

y = c_{1} t^{\frac{3}{2}}

y = c_{1} t^{\frac{3}{2}}

Graph

Popular Examples

tangent of f(x)= 7/(x^4),\at x=-3 tangent of

f (x) = \frac{7}{x ^{4}}, at x = - 3

tangent of y=sqrt(x+2),(-1,1)tangent of

y = x + 2, (- 1, 1)

(dy)/(dx)=(y^2+xy+x^2)/(x^2),y(1)=-1

\frac{d y}{d x} = \frac{y ^{2} + x y + x ^{2}}{x ^{2}}, y (1) = - 1

limit as x approaches-4+of (-2)/(x^2-16)

x \to - 4 + lim (\frac{- 2}{x ^{2} - 16})

(\partial)/(\partial x)(ln(x/4))

\frac{\partial}{\partial x} (ln (\frac{x}{4}))

Frequently Asked Questions (FAQ)

What is the solution for 2ty^'-3y=0 ?
The solution for 2ty^'-3y=0 is y=c_{1}t^{3/2}